triangler prisim has 8 as Hight 6 a base 9 as length and 5 as width
solve for surface area
To find the surface area of a triangular prism, we need to calculate the area of each of the three rectangular faces and the two triangular faces.
First, let's find the area of the three rectangular faces:
Each rectangular face will have a length of 9 and a width of 5.
Area of one rectangular face = length x width
Area of one rectangular face = 9 x 5 = 45 square units
As there are three rectangular faces, the total area of the rectangular faces = 3 x 45 = 135 square units
Now, let's find the area of the two triangular faces:
Each triangular face will have a base of 9 and a height of 8.
Area of one triangular face = (1/2) x base x height
Area of one triangular face = (1/2) x 9 x 8 = 36 square units
As there are two triangular faces, the total area of the triangular faces = 2 x 36 = 72 square units
Finally, the total surface area of the triangular prism is the sum of the areas of the rectangular and triangular faces:
Total surface area = 135 + 72 = 207 square units
Therefore, the surface area of the triangular prism with dimensions 8 (height), 6 (base), 9 (length), and 5 (width) is 207 square units.