If the weights of carbon, hydrogen, and oxygen are approximately 12, 1, and 16 g/mol respectively, about how much would 1 mole of sucrose (C6H12O6) weigh?
To find the molecular weight of sucrose (C6H12O6), we need to multiply the number of atoms of each element by their respective weights and then sum them up.
Molecular weight of sucrose = 6(12 g/mol) + 12(1 g/mol) + 6(16 g/mol)
= 72 g/mol + 12 g/mol + 96 g/mol
= 180 g/mol
Therefore, 1 mole of sucrose would weigh approximately 180 grams.