Madelyn bowled 6 games at a bowling alley. Her scores were as follows:
211, 183, 162, 151, 202, 195
What was Madelyn’s mean score for the 6 games?
(1 point)
Responses
182
182
184
184
202
202
364
364
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To find the mean score, we add up all the scores and divide by the total number of games:
(211 + 183 + 162 + 151 + 202 + 195) / 6 = 1104 / 6 = 184
Therefore, Madelyn's mean score for the 6 games was 184.
The correct answer is 184.
The percentage of children living in single-parent households in America’s five most populated cities is: Philadelphia 40.4%, New York, 30.5 %, Chicago 32.2%, Houston 26%, and Los Angles 25.8%.
What is the range of this data?
(1 point)
Responses
154.9%
154.9%
100.0%
100.0%
30.98%
30.98%
14.6%
14.6%
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The range of the data is the difference between the maximum and minimum values in the dataset. In this case, the maximum value is 40.4% (Philadelphia) and the minimum value is 25.8% (Los Angeles).
The range is 40.4% - 25.8% = 14.6%
Therefore, the range of this data is 14.6%.
The correct answer is 14.6%.
Ms. Thompson collected data to determine the number of students absent for each month of school during the first semester. Identify the outlier in her data.
(1 point)
Responses
August
August
December
December
June
June
October
October
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To identify an outlier in a set of data, you would look for a value that is significantly different from the rest of the values. In this case, the months represent the data points.
In a typical school setting, June would be an outlier in this context because it is not within the typical range of the school year and is likely not a month where school is typically in session.
Therefore, the outlier in Ms. Thompson's data is June.
Zunaira is tracking the number of rebounds she has in each of her basketball games. The dot plot below shows her rebound data for the season.
Which measure of center should Zunaira use to analyze her data? Why?
(1 point)
Responses
Zunaira should use the median because the data is roughly symmetric.
Zunaira should use the median because the data is roughly symmetric.
Zunaira should use the median because the outlier at 12 will skew the mean.
Zunaira should use the median because the outlier at 12 will skew the mean.
Zunaira should use the mean because the data is roughly symmetric.
Zunaira should use the mean because the data is roughly symmetric.
Zunaira should use the mean because the data is skewed left.
Zunaira should use the mean because the data is skewed left.
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Zunaira should use the median because the outlier at 12 will skew the mean.
The data in the dot plot shows one outlier (at 12) that significantly differs from the rest of the data. When there is an outlier present, the mean can be heavily influenced by it and may not give an accurate representation of the typical or central value. The median, on the other hand, is not as affected by outliers and can provide a more robust measure of center.
Therefore, Zunaira should use the median to analyze her data in this case.
Consider the data set: {9, 8, 2, 16, 16, 16, 12, 10, 26, 27, 25, 34, 30, 34, 37, 46, 43, 43, 43, 43}(1 point)
Responses
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