Lesson nine unit six surface area of cylinders use the image to answer the question we have on the bottom 10 inches on the right side 9 inches and on the top 10 inches it says find the surface area of the net diagram of the right circular cylinder use 3.14 for Tt what would the answer be in inches?
To find the surface area of the net diagram of the right circular cylinder, we need to find the area of each face (top, bottom, and side) and add them together.
1. Top and bottom faces:
The top and bottom faces of the cylinder are circles with a radius of 5 inches (half of the diameter of 10 inches). The formula to find the area of a circle is A = πr^2, where r is the radius.
A = π(5)^2
A = π(25)
A = 25π
Since we are using 3.14 for π, the area of each circle is:
A = 25 * 3.14
A = 78.5 square inches
Since there are two circles (top and bottom), the total area for the top and bottom faces is:
2 * 78.5 = 157 square inches
2. Side face:
The side face of the cylinder is a rectangle with a height of 9 inches and a length equal to the circumference of the circle (2πr). The circumference of the circle is:
C = 2π(5)
C = 10π
The area of the side face is:
A = height * length
A = 9 * 10π
A = 90π
Since we are using 3.14 for π, the area of the side face is:
A = 90 * 3.14
A = 282.6 square inches
3. Total surface area:
The total surface area of the right circular cylinder is the sum of the areas of the top, bottom, and side faces:
Total surface area = 157 + 282.6
Total surface area = 439.6 square inches
Therefore, the surface area of the net diagram of the right circular cylinder is 439.6 square inches.