Lesson 10 graphing linear equations portfolio
In this lesson, we learned how to graph linear equations on a coordinate plane. To demonstrate our understanding, we will create a portfolio showcasing our work.
Task 1: Graphing a Linear Equation
First, we will graph the equation y = 2x + 3 on a coordinate plane. Remember that this equation is in slope-intercept form (y = mx + b), where the slope is 2 and the y-intercept is 3.
To graph this equation, we will start by plotting the y-intercept at (0, 3). Then, using the slope of 2, we will move up 2 units and right 1 unit to plot another point. Connecting these two points will give us a straight line representing the equation y = 2x + 3.
Task 2: Finding the Slope and y-Intercept
Next, we will find the slope and y-intercept of the equation 3x - 4y = 8. To do this, we will rewrite the equation in slope-intercept form by solving for y.
3x - 4y = 8
-4y = -3x + 8
y = 3/4x - 2
From this, we can see that the slope is 3/4 and the y-intercept is -2.
Task 3: Graphing Another Linear Equation
Finally, we will graph the equation y = -3x + 5 on a coordinate plane. This equation is already in slope-intercept form, with a slope of -3 and a y-intercept of 5.
Following the same steps as before, we will plot the y-intercept at (0, 5) and use the slope of -3 to find another point on the line. Connecting these points will give us the graph of y = -3x + 5.
By completing these tasks and showcasing our work in a portfolio, we have demonstrated our ability to graph linear equations and understand their key components such as slope and y-intercept.