Determine the theoretical percent composition of water in bluestone
To determine the theoretical percent composition of water in bluestone (CuSO4·5H2O), we need to consider the molar mass of the compound.
The molar mass of CuSO4·5H2O can be calculated as follows:
Copper (Cu): 1 atom x 63.5 g/mol = 63.5 g/mol
Sulfur (S): 1 atom x 32.1 g/mol = 32.1 g/mol
Oxygen (O): 4 atoms x 16.0 g/mol = 64.0 g/mol
Hydrogen (H): 10 atoms x 1.0 g/mol = 10.0 g/mol
Total molar mass = 63.5 + 32.1 + 64.0 + 10.0 = 169.6 g/mol
Now, we need to calculate the mass of water (5H2O) in the compound:
Water (H2O): 5 molecules x 18.0 g/mol = 90.0 g/mol
The percent composition of water in bluestone can be calculated as:
(90.0 g/mol / 169.6 g/mol) x 100% = 53.0%
Therefore, the theoretical percent composition of water in bluestone is 53.0%.