Graph this line using the slope and y-intercept:
y=5x+3
To graph the line y=5x+3, we first start by plotting the y-intercept, which is 3.
This gives us the point (0, 3). Next, we use the slope of 5 to find another point on the line.
The slope of 5 means that for every 1 unit we move to the right, we need to move 5 units up.
Starting from the y-intercept at (0, 3), we move 1 unit to the right and 5 units up to get the point (1, 8).
We can continue this pattern to find more points on the line.
Plotting these points and connecting them will give us the graph of the line y=5x+3.
The graph will be a straight line that slopes upwards, with a y-intercept at 3.
Graph this line using the slope and y-intercept:
y=
1
5
x+1
The equation given is y = (1/5)x + 1.
To graph this line, start by plotting the y-intercept which is 1. This gives us the point (0, 1).
Next, use the slope of 1/5. This means for every 1 unit we move to the right, we move up 1/5 units. Starting from the y-intercept at (0, 1), move 5 units to the right and then 1 unit up to get the point (5, 2).
Plot these points and then draw a straight line through them. This will be the graph of the line y = (1/5)x + 1, which will have a positive slope and pass through the y-intercept at (0, 1).
Graph this line using the slope and y-intercept:
y=
1
4
x+6
The equation given is y = (1/4)x + 6.
To graph this line, start by plotting the y-intercept which is 6. This gives us the point (0, 6).
Next, use the slope of 1/4. This means for every 1 unit we move to the right, we move up 1/4 units. Starting from the y-intercept at (0, 6), move 4 units to the right and then 1 unit up to get the point (4, 7).
Plot these points and then draw a straight line through them. This will be the graph of the line y = (1/4)x + 6, which will have a positive slope and pass through the y-intercept at (0, 6).