A bowling ball is traveling at 7.6 meters per second when it hits a pin.
If the bowling ball has a mass of 6 kilograms, how much kinetic energy
does it have when it hits the pin?
(1 point)
KE =
1
2mv
2
693.12 J
173.28 J
346.65 J
22.8 J
To find the kinetic energy of the bowling ball when it hits the pin, we can use the formula for kinetic energy:
KE = 1/2mv^2
Where:
m = mass of the bowling ball = 6 kg
v = velocity of the bowling ball = 7.6 m/s
Now, plug in the values:
KE = 1/2 * 6 kg * (7.6 m/s)^2
KE = 1/2 * 6 kg * 57.76 m^2/s^2
KE = 3 * 57.76 kg m^2/s^2
KE = 173.28 J
Therefore, the kinetic energy of the bowling ball when it hits the pin is 173.28 J.
So, the answer is:
KE = 173.28 J