A toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number.
(1 point)
S.A. = cm2
To calculate the surface area of the triangular prism container, we first need to find the area of the three faces.
Let's assume the triangular base of the prism has a base of b cm and a height of h cm.
The area of each triangular face is:
(1/2) * base * height
Since there are two triangular faces on the sides of the prism, the total area of both triangular faces is:
2 * (1/2) * b * h = b * h
Now, let's calculate the area of the rectangular face at the bottom of the prism. The base of the triangle would be the same as the base of the prism (b cm) and the height would be the same as the height of the prism (h cm). Therefore, the area of the rectangular face is:
b * h
So, the total surface area (S.A.) of the triangular prism container is:
(2 * b * h) + (b * h) = 3 * b * h
Now, if we round this value to the nearest whole number, we will get the amount of wrapping paper needed to wrap the toy.
Hence, the amount of wrapping paper needed is approximately 3 * b * h cm².