What is the surface area of a rectangular prism whose dimensions are 334 dm×412 dm×5 dm in square decimeters?(1 point) Responses 11614 dm2 116 Start Fraction 1 over 4 End Fraction dm squared 5818 8 dm2 58 Start Fraction 1 over 8 End Fraction dm squared 8438 dm2 84 Start Fraction 3 over 8 End Fraction dm squared 16 dm2
The formula for calculating the surface area of a rectangular prism is 2lw + 2lh + 2wh, where l, w, and h are the length, width, and height of the prism respectively.
Given:
Length (l) = 334 dm
Width (w) = 412 dm
Height (h) = 5 dm
Surface Area = 2(334*412) + 2(334*5) + 2(412*5)
Surface Area = 2(137888) + 2(1670) + 2(2060)
Surface Area = 275776 + 3340 + 4120
Surface Area = 283236 dm^2
Therefore, the surface area of the rectangular prism is 283236 dm^2.