The molar mass of BF3 is 67.81 g/mol. How many molecules of BF3 are there in 2 g?(1 point)
Responses
1.776×1022
1 point 7 7 6 times 10 to the 22th power
4.084×1025
4 point 0 8 4 times 10 to the 25th power
1.204×1024
1 point 2 0 4 times 10 to the 24th power
8.881×1021
To find the number of molecules in 2g of BF3, we first need to convert 2g to moles.
Moles = mass / molar mass
Moles = 2g / 67.81 g/mol
Moles = 0.0295 mol
Now, we know that 1 mole of BF3 contains 6.022 x 10^23 molecules (Avogadro's number).
Number of molecules = moles x 6.022 x 10^23
Number of molecules = 0.0295 mol x 6.022 x 10^23
Number of molecules = 1.776 x 10^22
Therefore, there are 1.776 x 10^22 molecules of BF3 in 2g.
So, the correct answer is: 1.776×10^22.