What is the value of n so that the expression x^2 + 11x + n is a perfect square trinomial
To find the value of n so that the expression x^2 + 11x + n is a perfect square trinomial, we need to find a value of n such that the middle term (11x) can be expressed as 2 times the square root of the product of the first and third terms.
In this case, the first term is x^2 and the third term is n. So, we need to have:
11x = 2*sqrt(x^2*n)
Expanding the square root on the right side gives:
11x = 2*sqrt(x^2*n)
11x = 2*sqrt(n)*x
Now, we can see that n = (11/2)^2 = 121/4.
So, the value of n that makes the expression x^2 + 11x + n a perfect square trinomial is n = 121/4.