a spinner is labeled with the letters of the word HONEST is to be spun once. describe the probability of landing on an unshaded section in the sample space.
1/3
1/6
1/2
or 3
1/3
Choosing a ball from a bag and then choosing another ball without replacing the first is a dependent event because the outcome of the first event affects the probability of the second event.
The total number of fruits in the basket is 5 (bananas) + 8 (mangoes) + 7 (apples) = 20.
The probability of selecting an apple on the first draw is 7/20.
After selecting one apple, there are 19 fruits remaining in the basket, and the probability of selecting a banana on the second draw is 5/19.
To find the probability of selecting an apple and then a banana, we multiply the probabilities of each event:
P(apple and banana) = (7/20) * (5/19) = 35/380 = 7/76
Therefore, the probability of selecting an apple and a banana from the basket is 7/76.
The total number of fruits in the basket is 10 (bananas) + 5 (mangoes) + 5 (apples) = 20.
The probability of selecting an apple is 5/20 and the probability of selecting a banana is 10/20.
To find the probability of selecting either an apple or a banana, we add the individual probabilities because these are mutually exclusive events.
P(apple or banana) = P(apple) + P(banana) = 5/20 + 10/20 = 15/20 = 3/4
To express the answer in percent form, we multiply the probability by 100%:
P(apple or banana) = 3/4 * 100% = 75%
Therefore, the probability of selecting an apple or a banana from the basket is 75%.
Let A be the event of selecting a student who wants the option to keep studying online, and B be the event of selecting a boy.
The probability of selecting a student who wants to keep studying online (A) is given by P(A) = (number of students who want to keep studying online) / (total number of students) = 13 / 25.
The probability of selecting a boy (B) is given by P(B) = (number of boys) / (total number of students) = 10 / 25.
The probability of selecting a student who wants to keep studying online OR a boy is the sum of the probabilities of the individual events minus the probability of selecting a student who wants to keep studying online AND a boy (since these events are mutually exclusive):
P(A or B) = P(A) + P(B) - P(A and B)
Substitute the values:
P(A or B) = 13/25 + 10/25 - (3/25) = 20/25 = 4/5
Therefore, the mathematical sentence to calculate the probability of selecting a student who wants the option to keep studying online or is a boy is P(A or B) = 4/5.
which set of events is dependant
choosing a ball from a bag and then choosing another pall wihtout replacing the first
choosing a marble from a box replacing it then choosing another marble
rolling a number cube and flipping a coin
the event of getting two heads when flipping two fiar coins
a basket of fruits contains 5 bannanas 8 mangoes and 7 apples two fruits are randomly selected without replacement caculate the probability of selecting a apple and a bannana
a basket of fruits contains 10 bannanas 5 mangoes and 5 apples a fruit is selected at random caculate the rpobability of selecting an apple or an bannana express the answer in precent form
what mathematical sentence can be used to caculate the probability of selecting a student who wants the option to keep stuying online or is a boy
wants to keep stuying online= 10 girls and 3 boys 13 total
dont want to keep stuying online = 5 girls and 7 boys 12 total
column total = 15, 10, 25