-4x+6y=38 x-5y=-20

To solve this system of equations, we can use either substitution or elimination method.

Let's use the elimination method in this case.

-4x + 6y = 38 ... (1)
x - 5y = -20 ... (2)

To eliminate x, we can multiply the second equation by 4:

4(x - 5y) = 4(-20)
4x - 20y = -80

Now we can add this new equation to the first equation:

-4x + 6y + 4x - 20y = 38 - 80
-14y = -42
y = 3

Now we can substitute y back into equation (2) to solve for x:

x - 5(3) = -20
x - 15 = -20
x = -20 + 15
x = -5

Therefore, the solution to the system of equations is x = -5, y = 3.