Which of the following equations has an infinite number of solutions?

Question

(1 point)
Responses

3x – 3 = –4x
3 x – 3 = –4 x

2y + 4 – y = 16
2 y + 4 – y = 16

7x + 5 = 4x + 5 + 3x
7 x + 5 = 4 x + 5 + 3 x

6y – 2 = 2(y – 1)

Answer 1

The equation 6y - 2 = 2(y - 1) has an infinite number of solutions. This is because when you solve the equation by distributing the 2 on the right side, the variable y will cancel out, leaving a true statement that is always true regardless of the value of y.