What’s the heat of this reaction: C2H4 (g) + H2O (g) —-> C2H5OH (l)
The heat of reaction can be found by looking up the standard enthalpies of formation for each compound involved in the reaction and using them to calculate the overall enthalpy change of the reaction.
The standard enthalpies of formation for C2H4 (g), H2O (g), and C2H5OH (l) are:
C2H4 (g): 52.3 kJ/mol
H2O (g): -241.8 kJ/mol
C2H5OH (l): -276.0 kJ/mol
Using these values, we can calculate the overall enthalpy change of the reaction:
ΔH = Σ(products) - Σ(reactants)
ΔH = (-276.0 kJ/mol) - [(-241.8 kJ/mol) + (52.3 kJ/mol)]
ΔH = -276.0 kJ/mol + 193.5 kJ/mol
ΔH = -82.5 kJ/mol
Therefore, the heat of the reaction C2H4 (g) + H2O (g) —-> C2H5OH (l) is -82.5 kJ/mol.