Solve the system of equations by substitution. −4x+4y=−40 y=3x−4 This question requires you to show your work. (1 point) Responses (−3,−13) open paren negative 3 comma negative 13 close paren (6, 4) (6, 4) (3, 7) (3, 7) (1,−1)

Question

Solve the system of equations by substitution. −4x+4y=−40 y=3x−4 This question requires you to show your work. (1 point) Responses (−3,−13) open paren negative 3 comma negative 13 close paren (6, 4) (6, 4) (3, 7) (3, 7) (1,−1)

Answer 1

First, we plug in the expression for y into the first equation:

-4x + 4(3x - 4) = -40
-4x + 12x - 16 = -40
8x - 16 = -40

Adding 16 to both sides:
8x = -24

Divide by 8:
x = -3

Now, substitute x back into the second equation to solve for y:
y = 3(-3) - 4
y = -9 - 4
y = -13

Therefore, the solution is (-3, -13).