Which of the following systems of equations has the solution (-2, 1)?
This question requires you to show your work.
(1 point)
Responses
y=−3/2x−2
and 2x−y=−5
y is equal to negative 3 over 2 x minus 2 and 2 x minus y is equal to negative 5
x−4y=8
and 3x+10=−2y
x minus 4 y is equal to 8 and 3 x plus 10 is equal to negative 2 y
y=−2x−2
and 2x−2y=5
y is equal to negative 2 x minus 2 and 2 x minus 2 y is equal to 5
2x−y=−5
and x+2y=10
To find the solution to the system of equations, we need to substitute x = -2 and y = 1 into each equation to see which system satisfies both equations.
For the first system:
y = -3/2x - 2
1 = -3/2(-2) - 2
1 = 3 + 2
1 = 5 (This system does not satisfy the first equation)
2x - y = -5
2(-2) - 1 = -5
-4 - 1 = -5
-5 = -5 (This system satisfies the second equation)
Therefore, the system of equations 2x - y = -5 and x + 2y = 10 has the solution (-2, 1).
Pick one option
Based on the calculations provided, the system of equations with the solution (-2, 1) is:
2x - y = -5
and
x + 2y = 10
So, the correct option is:
2x − y = −5
and x + 2y = 10