If a certain gas occupies a volume of 18 L
when the applied pressure is 9.0 atm
, find the pressure when the gas occupies a volume of 4.5 L
.
To find the pressure when the gas occupies a volume of 4.5 L, we can use the combined gas law formula:
P1V1 = P2V2
Where:
P1 = initial pressure = 9.0 atm
V1 = initial volume = 18 L
P2 = final pressure (unknown)
V2 = final volume = 4.5 L
Plugging in the values we know:
(9.0 atm)(18 L) = P2(4.5 L)
Solving for P2:
P2 = (9.0 atm * 18 L) / 4.5 L
P2 = 36 atm
Therefore, the pressure when the gas occupies a volume of 4.5 L is 36 atm.