A sample of radon gas has a volume of 1.53 L, a pressure of 1.15 atm, and a temperature of 305 K. What is the new pressure, if the new volume is 1.78 L and the new temperature is 325 K?
Assuming the amount of gas and number of moles remains constant, we can use the combined gas law to solve for the new pressure:
P1V1 / T1 = P2V2 / T2
Plugging in the given values:
(1.15 atm)(1.53 L) / 305 K = P2(1.78 L) / 325 K
Solving for P2:
P2 = (1.15 atm)(1.53 L)(325 K) / (1.78 L)(305 K)
P2 = 1.33 atm
Therefore, the new pressure would be 1.33 atm.