A sample of carbon monoxide gas has a volume of 3.45 L and a pressure of 2.82 atm, under a constant temperature of 28 °C. What is the new volume, if the pressure is increased to 4.2 atm?
To solve this problem, we can use the combined gas law formula:
(P1)(V1) = (P2)(V2)
Where:
P1 = initial pressure = 2.82 atm
V1 = initial volume = 3.45 L
P2 = final pressure = 4.2 atm
V2 = final volume = ?
Now, plug in the values:
(2.82 atm)(3.45 L) = (4.2 atm)(V2)
Solve for V2:
V2 = (2.82 atm)(3.45 L) / 4.2 atm
V2 = 2.31375 L
Therefore, the new volume of the carbon monoxide gas at a pressure of 4.2 atm is approximately 2.31 L.