A sample of sulfur dioxide gas has a volume of 0.871 L and a temperature of 315 K, under a constant pressure. What is the new volume, if the temperature is increased to 385 K?
To solve this problem, we can use the combined gas law which states:
(V1 / T1) = (V2 / T2)
Where:
V1 = initial volume (0.871 L)
T1 = initial temperature (315 K)
V2 = final volume (unknown)
T2 = final temperature (385 K)
Plugging in the values:
(0.871 L / 315 K) = (V2 / 385 K)
Cross multiplying:
0.871 * 385 = V2 * 315
V2 = (0.871 * 385) / 315
V2 = 1.067 L
Therefore, the new volume of the sulfur dioxide gas when the temperature is increased to 385 K is 1.067 L.