A baseball diamond is a square with sides of 90 feet. What is the shortest distance between first base and third base?
A baseball diamond is a square with sides of 90 feet. What is the shortest distance between first base and third base?
The shortest distance between first base and third base on a baseball diamond can be calculated using the Pythagorean theorem since it forms a right triangle.
The diagonal of a square is √2 times the length of the side. Given that the side length of the square (basepath) is 90 feet, the diagonal (the shortest distance between first base and third base) can be calculated as:
Diagonal = √2 * side
Diagonal = √2 * 90
Diagonal = 127.28 feet (approx.)
Therefore, the shortest distance between first base and third base on a baseball diamond is approximately 127.28 feet.