What is the vertex form of the equation?
y= -x^2+12x-4
To find the vertex form of the equation y = -x^2 + 12x - 4, we first need to complete the square.
Starting with the given equation y = -x^2 + 12x - 4:
y = -(x^2 - 12x) - 4
y = -(x^2 - 12x + 36) + 36 - 4 (since we need to add and subtract (b/2)^2 to complete the square)
y = -(x - 6)^2 + 32
Therefore, the vertex form of the equation y = -x^2 + 12x - 4 is y = -(x - 6)^2 + 32.