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To solve this system of equations, we can use either the substitution or elimination method.
Let's use the elimination method here:
1. Multiply the first equation by 5 and the second equation by 3 to make the coefficients of X the same:
15X + 30Y = 105
-15X + 6Y = 39
2. Add the two equations together:
36Y = 144
3. Solve for Y:
Y = 4
4. Substitute this value of Y back into one of the original equations:
3X + 6(4) = 21
3X + 24 = 21
3X = -3
X = -1
Therefore, the solution to the system of equations is X = -1 and Y = 4.