A hydrated salt of formula MSO4•SH2O contain 45.3% by mass of the water of crystalization.calculate the value of x(M=56,S=32,O=16,H=1)
What is x
To calculate the value of x, we first need to determine the molecular weight of the hydrated salt and the molecular weight of the water of hydration.
Molecular weight of MSO4•SH2O:
Molecular weight of M = 56
Molecular weight of S = 32
Molecular weight of O = 16
Molecular weight of H = 1
Molecular weight of water (H2O) = 2(1) + 16 = 18
Total molecular weight of MSO4•SH2O:
56 + 32 + 4(16) + 18 = 56 + 32 + 64 + 18 = 170
Now, calculate the mass of water in the hydrated salt:
Let's assume the mass of the hydrated salt is 100g.
The mass of water in the hydrated salt is 45.3% of its mass, which is 45.3g.
Now, let's calculate the amount of MSO4 in 100g of hydrated salt:
Mass of MSO4 = 100g - 45.3g = 54.7g
Calculate the moles of MSO4:
54.7g / 170g/mol = 0.3217 mol
From the formula MSO4•xH2O, we can see that there is one S atom in the formula, therefore the value of x is 1.