Determine the slope line 5/3 - 5/3 3/5 - 3/5 right in linear equations in slope intercept form
To determine the slope of the line passing through the points (5/3, -5/3) and (3/5, -3/5), we can use the slope formula:
m = (y2 - y1) / (x2 - x1)
Where:
Point 1 = (x1, y1) = (5/3, -5/3)
Point 2 = (x2, y2) = (3/5, -3/5)
Plugging in the values:
m = (-3/5 + 5/3) / (3/5 - 5/3)
m = (-15/15 + 25/15) / (9/15 - 25/15)
m = (10/15) / (-16/15)
m = 10/15 * -15/16
m = -1
Therefore, the slope of the line passing through the points (5/3, -5/3) and (3/5, -3/5) is -1.
To write the equation of the line in slope-intercept form (y = mx + b), we can choose one of the points (5/3, -5/3) and use the slope we found:
y = -x + b
Plugging in the point (5/3, -5/3):
-5/3 = -5/3 + b
b = 0
Therefore, the equation of the line passing through the points (5/3, -5/3) and (3/5, -3/5) is:
y = -x
or
y = -1x
where the slope (m) is -1 and the y-intercept (b) is 0.