Use the image to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 30 in increments of 2. Multiple points are plotted around a line that points upward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 12 right parenthesis, left parenthesis 4 comma 16 right parenthesis, and left parenthesis 6 comma 18 right parenthesis. 12 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
y=
2x+10
thats wrong
I apologize for the mistake. Let's find the equation of the trend line more accurately.
Given the points (0, 12), (4, 16), and (6, 18) on the trend line, we can calculate the slope of the line using the formula:
slope = (y2 - y1) / (x2 - x1)
Using the points (0, 12) and (4, 16):
slope = (16 - 12) / (4 - 0) = 4 / 4 = 1
Now that we have the slope, we can use one of the points, such as (0, 12), and the slope to find the y-intercept. Using the slope-intercept form of a line, which is y = mx + b (where m is the slope and b is the y-intercept):
12 = 1(0) + b
b = 12
Therefore, the equation of the trend line in slope-intercept form is:
y = x + 12