2 C8H18 (g) + 25 02(g) →16 C02(g) + 18H20(g)
After the reaction, how much octane is left?
Express your answer with the appropriate units.
To determine how much octane is left after the reaction, we need to compare the stoichiometry of octane in the reactants to the products.
From the balanced chemical equation, we see that 2 moles of octane (C8H18) react with 25 moles of oxygen (O2) to produce 16 moles of carbon dioxide (CO2) and 18 moles of water (H2O).
If we start with 2 moles of octane and calculate the moles of octane consumed in the reaction, we get:
2 moles octane - 2 moles octane = 0 moles octane remaining
Therefore, after the reaction, there is 0 moles of octane left.
Since the molar mass of octane (C8H18) is approximately 114.23 g/mol, we can calculate the amount of octane left in grams:
0 moles octane * 114.23 g/mol = 0 g octane
Therefore, there is 0 grams of octane left after the reaction.