a hummingbird with an initial velocity of 12.0m/s [N] flies 450m [N] to the next flower along a straight line with constant acceleration in 25.0s what is the bird's final velocity as it reaches the next flower
To find the final velocity of the hummingbird, we can use the following kinematic equation:
v_f = v_i + at
Where:
v_f = final velocity
v_i = initial velocity
a = acceleration
t = time
Given:
v_i = 12.0 m/s [N]
a = unknown
t = 25.0 s
First, let's calculate the acceleration using the formula:
a = (v_f - v_i) / t
We are trying to find the final velocity, so let's rearrange the formula to solve for acceleration:
a = (v_f - 12.0) / 25.0
Since the hummingbird starts at rest and has an initial velocity of 12.0 m/s [N], the final velocity at the end of 25.0 seconds will be:
450m = 0*25 + (1/2)a(25)^2
a= 450/625
v_f = 12.0 + (450/625)*25
v_f = 12.0 + 18.0
v_f = 30.0 m/s
Therefore, the bird's final velocity as it reaches the next flower is 30.0 m/s [N].