Question

Graph the quadratic y=4x^2+3x−8 . What is the vertex of this quadratic?(1 point)

Responses

(−1.838,0)
left parenthesis negative 1.838 comma 0 right parenthesis

(1.088,0)
left parenthesis 1.088 comma 0 right parenthesis

(−0.375,−8.563)
left parenthesis negative 0.375 comma negative 8.563 right parenthesis

(0,−8)
left parenthesis 0 comma negative 8 right parenthesis

Answer 1

[AI-generated answer — Bot GPT 3.5]

To graph the quadratic y=4x^2+3x−8, we can first find the x-coordinate of the vertex using the formula x = -b/2a.

In this case, a=4 and b=3. Plug these values into the formula:

x = -3 / 2*4 = -3 / 8 = -0.375

So, the x-coordinate of the vertex is -0.375.

To find the y-coordinate of the vertex, plug this x-value back into the equation:

y = 4(-0.375)^2 + 3(-0.375) - 8
y = 4(0.140625) - 1.125 - 8
y = 0.5625 - 1.125 - 8
y = -8.5625

Therefore, the vertex of the quadratic y=4x^2+3x−8 is (-0.375, -8.563).

Answer: (−0.375,−8.563)