A quadratic function y, equals, f, of, xy=f(x) is plotted on a graph and the vertex of the resulting parabola is left bracket, minus, 4, comma, minus, 5, right bracket(−4,−5). What is the vertex of the function defined as g, of, x, equals, f, of, x, plus, 3g(x)=f(x)+3?
Since the vertex of the original function is at (-4, -5), we know that the vertex of the function g(x) = f(x) + 3 will also have a y-coordinate that is 3 units greater than that of f(x).
Therefore, the vertex of function g(x) will be at (-4, -5 + 3) or (-4, -2).