Which of the following systems of equations has the solution (-2, 1)?
This question requires you to show your work.
(1 point)
Responses
2x−y=−5
and x+2y=10
2 x minus y is equal to negative 5 and x plus 2 y is equal to 10
x−4y=8
and 3x+10=−2y
x minus 4 y is equal to 8 and 3 x plus 10 is equal to negative 2 y
y=−3/2x−2
and 2x−y=−5
y is equal to negative 3 over 2 x minus 2 and 2 x minus y is equal to negative 5
y=−2x−2
and 2x−2y=5
Let's plug in the solution (-2, 1) into the pairs of equations given:
For the first pair:
2(-2) - 1 = -5
-4 - 1 = -5
-5 = -5
-2 + 2(1) = 10
-2 + 2 = 10
0 ≠ 10
The solution (-2, 1) does not satisfy the first system of equations.
For the second pair:
(-2) - 4(1) = 8
-2 - 4 = 8
-6 ≠ 8
3(-2) + 10 = -2(1)
-6 + 10 = -2
4 = -2
The solution (-2, 1) does not satisfy the second system of equations.
For the third pair:
1 = -3/2(-2) - 2
1 = 3 + 2
1 = 5
2(-2) - 1 = -5
-4 - 1 = -5
-5 = -5
The solution (-2, 1) satisfies the third system of equations.
Therefore, the correct answer is:
y=−3/2x−2
and 2x−y=−5