Which of the following systems of equations has the solution (-2, 1)?
This question requires you to show your work.
(1 point)
Responses
x−4y=8
and 3x+10=−2y
x minus 4 y is equal to 8 and 3 x plus 10 is equal to negative 2 y
y=−2x−2
and 2x−2y=5
y is equal to negative 2 x minus 2 and 2 x minus 2 y is equal to 5
y=−32x−2
and 2x−y=−5
y is equal to negative 3 over 2 x minus 2 and 2 x minus y is equal to negative 5
2x−y=−5
and x+2y=10
To check if the solution (-2, 1) is a solution to the system of equations, substitute x = -2 and y = 1 into each equation.
For the system:
2x - y = -5
x + 2y = 10
Substitute x = -2 and y = 1:
2(-2) - 1 = -5
-4 - 1 = -5
-5 = -5
x + 2(1) = 10
-2 + 2 = 10
-2 + 2 = 10
Therefore, the system of equations 2x - y = -5 and x + 2y = 10 has the solution (-2, 1).