Part 2 of 3
x10
44.0 g C6H1206 in 3.83 L solution
M
Assuming the question is asking for the molarity of the C6H12O6 solution, we need to use the formula:
Molarity = (moles of solute) / (liters of solution)
First, we need to calculate the moles of C6H12O6:
Molar mass of C6H12O6 = 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol
moles = 44.0 g / 180.18 g/mol ≈ 0.244 moles
Now we can calculate the molarity:
Molarity = 0.244 moles / 3.83 L ≈ 0.0639 mol/L
Therefore, the molarity of the C6H12O6 solution is approximately 0.0639 mol/L.