A commercial rubbing alcohol contains 63. g of isopropanol and 0.331 g of sucrose octaacetate in each 77. -mL portion. Calculate the
concentration for each component. Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
weight
percent
volume
%
weight
volume
isopropanol
what is the answer please
81.8 is not the correct answer
The weight percent of isopropanol can be calculated by dividing the weight of isopropanol by the total weight of the solution (isopropanol + sucrose octaacetate):
(63. g / (63. g + 0.331 g)) x 100% = 99.5%
The volume percent of isopropanol can be calculated by dividing the volume of isopropanol by the total volume of the solution:
(63. g/ (63. g + 0.331 g)) x 100% = 99.5%
So the weight percent and volume percent of isopropanol in the solution are both 99.5%.