A commercial mouthwash contains 12.4 g of ethanol and 0.049 g of antiseptic in each 65. -mL portion. Calculate the

component. Be sure each of your answer entries has the correct number of significant figures.

Part 1 of 2

weight
volume
percent concentration for each

%

weight
volume

ethanol

Part 2 of 2

weight
volume

antiseptic

Part 1:

Ethanol:
Weight: 12.4 g
Volume: 65 mL
Percent concentration = (12.4 g / 65 mL) x 100% = 19.08%

Antiseptic:
Weight: 0.049 g
Volume: 65 mL
Percent concentration = (0.049 g / 65 mL) x 100% = 0.075%

Part 2:

Antiseptic:
Weight: 0.049 g
Volume: 65 mL