A running track in the shape of an oval is shown. The ends of the track form semicircles. What is the perimeter of the inside of the track? (5 points) (π = 3.14) it shows a circle which is 140m in length and up and down o. the inside its 68m
416.00 m
493.52 m
707.04 m
719.60 m
To find the perimeter of the inside of the track, we need to add the straight parts and the curved parts.
The straight parts are the two straight sides of the track.
The length of each straight side is 68m.
Adding both sides gives: 68m + 68m = 136m
The curved parts are the two semicircles.
The circumference of a full circle with a radius of 22m (which is half of the 44m width of the oval) is:
C = 2πr
C = 2 * 3.14 * 22
C ≈ 138.16m
Since we are dealing with two semicircles, each semicircle will be half of that, which is 69.08m.
Adding the straight parts to the curved parts:
136m + 69.08m + 69.08m = 274.16m
Therefore, the perimeter of the inside of the track is approximately 274.16m.