What is the distance between (19,-6) and (8,-6) on a coordinate plane
The distance between two points on a coordinate plane can be found using the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the points are (19, -6) and (8, -6).
Substitute the coordinates into the formula:
d = √((8 - 19)^2 + (-6 - (-6))^2)
d = √((-11)^2 + (0)^2)
d = √(121 + 0)
d = √121
d = 11
Therefore, the distance between (19, -6) and (8, -6) on a coordinate plane is 11 units.