Foil and Simply (x+1) (x+1)
First, let's expand the given expression by using the FOIL method, which stands for First, Outer, Inner, Last:
(x+1)(x+1)
= x*x + x*1 + 1*x + 1*1
= x^2 + x + x + 1
= x^2 + 2x + 1
Therefore, the expanded form of (x+1)(x+1) is x^2 + 2x + 1.
Alternatively, we can also simplify the expression:
(x+1)(x+1)
= x^2 + x + x + 1
= x^2 + 2x + 1
So, both the expanded and simplified forms yield the same result: x^2 + 2x + 1.
show me the steps to the answer
To expand the expression (x+1)(x+1) using the FOIL method, follow these steps:
1. First: Multiply the first terms in each parenthesis
(x + 1)(x + 1) equals x*x = x^2
2. Outer: Multiply the outer terms in each parenthesis
(x + 1)(x + 1) equals x*1 = x
3. Inner: Multiply the inner terms in each parenthesis
(x + 1)(x + 1) equals 1*x = x
4. Last: Multiply the last terms in each parenthesis
(x + 1)(x + 1) equals 1*1 = 1
5. Combine the results from steps 1 to 4 to get the final expanded form
(x + 1)(x + 1) = x^2 + x + x + 1
= x^2 + 2x + 1
Therefore, the expanded form of (x+1)(x+1) is x^2 + 2x + 1.