Joseph has a rain barrel in the shape of a cylinder with a height of 48 inches and a diameter of 24 inches. What is the surface area of the rain barrel? Use 3.14 for π and round to the nearest tenth.(1 point)
The formula for the surface area of a cylinder is:
2πr^2 + 2πrh
where r is the radius and h is the height of the cylinder.
Given that the diameter is 24 inches, the radius is half of the diameter, so r = 24 / 2 = 12 inches.
Now we can plug in the values into the formula:
2(3.14)(12)^2 + 2(3.14)(12)(48)
= 2(3.14)(144) + 2(3.14)(576)
= 2(452.16) + 2(1809.6)
= 904.32 + 3619.2
= 4523.52
Therefore, the surface area of the rain barrel is approximately 4523.5 square inches.
Nope
I apologize for the mistake. Let's correct it.
The formula for the surface area of a cylinder is:
2πr^2 + 2πrh
Given that the diameter is 24 inches, the radius is 12 inches.
Plugging in the values:
2(3.14)(12)^2 + 2(3.14)(12)(48)
= 2(3.14)(144) + 2(3.14)(576)
= 2(452.16) + 2(1809.6)
= 904.32 + 3619.2
= 4523.52
Rounded to the nearest tenth, the surface area of the rain barrel is approximately 4523.5 square inches. Thank you for your patience.