an object moves upward from rest with an acceleration of 39.24 m/s2 how long does it take to reach a height of 28.0 m assume uniform accelertion
To solve this problem, we can use the kinematic equation for displacement:
h = 0.5 * a * t^2
where:
h = height = 28.0 m
a = acceleration = 39.24 m/s^2
t = time taken to reach the height
Plugging in the values, we get:
28 = 0.5 * 39.24 * t^2
28 = 19.62 * t^2
t^2 = 1.425
Taking the square root of both sides, we get:
t = sqrt(1.425)
t = 1.194 seconds
Therefore, it takes approximately 1.194 seconds for the object to reach a height of 28.0 m.