an object moves forward from rest with a constant acceleration if the object moves 90.0 m in 7.00sfind its velocity after 7.00
To find the velocity after 7.00 seconds, we can use the following kinematic equation:
v = u + at
Where:
v = final velocity
u = initial velocity (in this case, since the object starts from rest, u = 0 m/s)
a = acceleration
t = time
Given that the object moves with a constant acceleration, we can find the acceleration using the following equation which relates distance, initial velocity, time, and acceleration:
s = ut + (1/2)at^2
Rearranging for acceleration (a), we have:
a = 2(s - ut)/t^2
Given:
s = 90 m
u = 0 m/s
t = 7.00 s
a = 2(90 - 0*7)/(7^2) = 180/49 m/s^2
Now, subtitute the known values into the first kinematic equation:
v = 0 + (180/49)*7
v = 1260/49
v = 25.714 m/s
Therefore, the velocity of the object after 7.00 seconds is 25.714 m/s.