A landscaping company places two orders with a nursery. The first order is for 13 trees and 4 bushes and totals to $753. The second order id for 6 trees and 2 bushes and totals to $352. How much does each tree and each bush cost?
Let the cost of each tree be x and the cost of each bush be y.
From the first order:
13x + 4y = 753 (equation 1)
From the second order:
6x + 2y = 352 (equation 2)
We can solve this system of equations by substitution or elimination. Let's use elimination:
Multiply equation 2 by 2:
12x + 4y = 704 (equation 3)
Now subtract equation 1 from equation 3:
12x + 4y - 13x - 4y = 704 - 753
-x = -49
x = 49
Now substitute x = 49 into equation 1:
13(49) + 4y = 753
637 + 4y = 753
4y = 116
y = 29
Therefore, each tree costs $49 and each bush costs $29.