If the position of the ladder is adjusted to reach the second floor window which is 25 feet high, how far will the base of the ladder be from the building?
(C: 50, B: 35.7, A: 35)
To find the distance from the base of the ladder to the building, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse (the ladder) is equal to the sum of the squares of the other two sides (the height of the window and the distance from the base to the building).
Let x be the distance from the base of the ladder to the building.
Using the Pythagorean theorem, we have:
x^2 + 25^2 = 50^2
x^2 + 625 = 2500
x^2 = 2500 - 625
x^2 = 1875
x ≈ √1875
x ≈ 43.3
Therefore, the distance from the base of the ladder to the building is approximately 43.3 feet. This answer is not listed in the options provided.