A ball is thrown from an initial height of 3 meters with an initial upward velocity of 15 m/s. The ball's height h (in meters) after & seconds is given by the following.
h = 3+ 15t-5t
²
where t is the time in seconds.
To find the height of the ball after 2 seconds, we plug in t = 2 into the equation:
h = 3 + 15(2) - 5(2)²
h = 3 + 30 - 20
h = 13
Therefore, the height of the ball after 2 seconds is 13 meters.