Find the area of the triangle. Use the formula sheet provided.
Numbers given: 9in 7in 13in 18in.
To find the area of a triangle given the lengths of its three sides (a, b, and c), we can use Heron's formula:
s = (a + b + c) / 2
Area = √[s(s - a)(s - b)(s - c)]
Given the numbers:
a = 9in, b = 7in, c = 13in
Calculate s:
s = (9 + 7 + 13) / 2
s = 29 / 2
s = 14.5
Now, calculate the area using Heron's formula:
Area = √[14.5(14.5 - 9)(14.5 - 7)(14.5 - 13)]
Area = √[14.5(5.5)(7.5)(1.5)]
Area = √2398.125
Area ≈ 48.97 square inches
Therefore, the area of the triangle with side lengths 9in, 7in, and 13in is approximately 48.97 square inches.
responses are:
A. 40 in^2
B. 63 in^2
C. 126 in^2
D. 47 in^2
Using the formula for the area of a triangle when sides are given A= √[s(s-a)(s-b)(s-c)],
where s is the semi-perimeter given by (a+b+c) / 2
First, calculate the semi-perimeter (s) for the given sides: a = 9in, b = 7in, c = 13in.
s = (9 + 7 +13) / 2
s = 29 / 2
s = 14.5
Now calculate the area using the formula:
Area = √[14.5(14.5 - 9)(14.5 - 7)(14.5 - 13)]
Area = √[14.5(5.5)(7.5)(1.5)]
Area = √[729.75]
Area ≈ 27 in^2
Therefore, the correct answer from the provided options is not included in the options given. The closest option to the actual area of the triangle is not listed.