What is the sum of the arithmetic series 18 t=1 (3t-4)
a. 234
b. 441
c. 25.5
d. 49
The sum of an arithmetic series can be calculated using the formula: n/2 * (first term + last term), where n is the number of terms.
In this case, the first term (t=1) is 3(1)-4 = -1 and the last term (t=18) is 3(18)-4 = 50.
n = 18
Sum = 18/2 * (-1 + 50) = 9 * 49 = 441
Therefore, the sum of the arithmetic series 18 t=1 (3t-4) is 441, so the answer is b. 441.