Suppose that 30% of a population carries a certain gene. You want to estimate the probability that it will take at least a sample of four to find a person that carries the gene, how could you simulate a person having or not having the gene?
Responses
A 0, 1, 2 could represent a person that carries the gene, and 3, 4, 5, 6, 7, 8, 9 could represent a person that does not carry the gene.0, 1, 2 could represent a person that carries the gene, and 3, 4, 5, 6, 7, 8, 9 could represent a person that does not carry the gene.
B 0, 1, 2, 3 could represent a person that carries the gene, and 4, 5, 6, 7, 8, 9 could represent a person that does not carry the gene.0, 1, 2, 3 could represent a person that carries the gene, and 4, 5, 6, 7, 8, 9 could represent a person that does not carry the gene.
C 0, 1, 2 could represent a person that does not carry the gene, and 3, 4, 5, 6, 7, 8, 9 could represent a person that carries the gene.0, 1, 2 could represent a person that does not carry the gene, and 3, 4, 5, 6, 7, 8, 9 could represent a person that carries the gene.
D 0, 1, 2, 3 could represent a person that does not carry the gene, and 4, 5, 6, 7, 8, 9 could represent a person that carries the gene.
D 0, 1, 2, 3 could represent a person that does not carry the gene, and 4, 5, 6, 7, 8, 9 could represent a person that carries the gene.
To simulate a person having or not having the gene, you could assign the numbers 0, 1, 2, 3 to represent a person that does not carry the gene and 4, 5, 6, 7, 8, 9 to represent a person that carries the gene. This way, when drawing a number randomly, there is a 30% chance of selecting a number that represents a person carrying the gene.