find the horizontal asymptote of the graph of y=3x^6-7x+10/8x^5+9x+10
To find the horizontal asymptote of the given function, we need to consider the limit of the function as x approaches positive or negative infinity.
The horizontal asymptote of a rational function is determined by the degrees of the numerator and denominator. In this case, the degree of the numerator is 6 and the degree of the denominator is 5.
When the degree of the numerator is greater than the degree of the denominator, the horizontal asymptote is y = 0.
Therefore, the horizontal asymptote of the graph of y = (3x^6 - 7x + 10) / (8x^5 + 9x + 10) is y = 0.